Question

A invests Rs. 10,000 and B invests Rs. 8000 at the same rate of interest per annum.  If at the end of 6 years, A gets Rs.600 more interest than B; find the rate of interest.​

Answer 1

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Answer 2

Answer:

Hey here u go ( pls mark as brainliest army )u just need to substitute different values

Step-by-step explanation:

It is given that P

′

s Investment =P

1

=Rs.36,000 and Q

′

s investment =P

2

=Rs.25,000

T=4 years

Let us consider the rate of investment R=x%

So we get P

′

s Interest (S.I)

1

=(P

1

×R×T)/100

Substituting the values =(36000×x×4)/100=Rs.1440x

Q

′

s interest (S.I)

2

=(P

2

×R×T)/100

Substituting the values =(25000×x×4)/100=Rs.1000x

The difference in their interest is calculated as (S.I)

1

−(S.I)

2

=1440x−1000x=Rs.440x

The difference given is =Rs.3080

So we get 440x=3080⇒x=3080/440⇒x=7

So the rate of interest R=7% p.a.