A invests Rs. 10,000 and B invests Rs. 8000 at the same rate of interest per annum. If at the end of 6 years, A gets Rs.600 more interest than B; find the rate of interest.
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Answer
interest=
100
p∗r∗t
p = principal amount , r = rate , t = time
interest=
100
10000∗5∗1
interest = RS. 500
Answered by
0
Answer:
rate of interest, R=5%
person A
principal amount, P = 10000
rate of interest =R
number of years, T =6
Interest Ia= (PRT)/100
Ia = ( 10000×R×6)/100
Ia = 600R
Person B
principal amount, P = 8000
rate of interest =R
number of years, T =6
Interest Ib= (PRT)/100
Ib = ( 8000×R×6)/100
Ib = 480R
given A gets ₹600more than B,
Ia = Ib+600
600R= 480R + 600
120R = 600
R=600/120
R= 5
rate of interest, R=5%
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