Question

A iron block weights 1/2 kg what is the weight of 20 such blocks what about 10​

Answer 1

Answer:

frictional force,

f

2

=(8+4)μ

k

=0.25×12=3N

If block A and B move with constant speed, then F should be equal to f

2

F=f

2

=3N

ii) In this case;

f

1

=μ

k

(4N)=0.25×4=1N

f

2

=3N

F=f

1

+f

2

=4N

iii) In this case, if B move with constant speed then A also move with constant speed but opposite direction.

F=T+f

1

+f

2

=1+1+3=5N

Step-by-step explanation:

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