Question

a iron pillar consists of a cylindrical portion of 2.8cm height and 20cm in diameter and a cone of 14 cm height surmouding on it find the heighr of the pillar 1cm cube iron 7 grms​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given,

An iron pillar consists of a cylindrical portion and a cone mounted on it.

The height of the cylindrical portion of the pillar, H=2.8 m=280 cm

The height of the conical portion of the pillar, h=42 cm

The diameter of the cylindrical portion of the pillar = diameter of the circular base of cone =D=20 cm

The radius of the circular base of cylinder/ cone r=

2

D

=10 cm

Now,

Volume of the pillar, (V)= Volume of the cylindrical portion of pillar + volume of the conical portion of the pillar.

→V=πr

2

H+

3

1

πr

2

h

→V=(

7

22

×10

2

×280+

3

1

×

7

22

×10

2

×42) cm

3

→V=(22×100×40+22×100×2) cm

3

→V=(88000+4400) cm

3

→V=92400 cm

3

Hence, volume of iron pillar is 92400 cm

3

Given,

Weight of 1 cm

3

iron =7.5 gm.

Hence, weight of 92400 cm

3

iron =7.5×92400 gm.

=693000 gm.

=693 Kg. ∵1Kg=1000 gm.

Hence, the weight of iron piller is 693 Kg.