A iron sphere of diameter 18 cm is drawn into a wire of diameter 4 mm. find the length of the wire.
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Sphere:
r1=9cm
Cylindrical wire:
r2=2mm
=0.2cm
Volume of sphere=Volume of cylindrical wire
(4/3)·π·r1^3=π·r2^2·h
On substituting
(4/3)·π·9·9·9=π·0.2·0.2·h
π gets canceled. Now bringing everything to one side except h.
h=4·9·9·9
3·0.2·0.2
By dividing
h=1·9·9·3 ·100
1·0.1·0.1 ·100
h=3·9·9·100
1·1·1
h=24300cm
r1=9cm
Cylindrical wire:
r2=2mm
=0.2cm
Volume of sphere=Volume of cylindrical wire
(4/3)·π·r1^3=π·r2^2·h
On substituting
(4/3)·π·9·9·9=π·0.2·0.2·h
π gets canceled. Now bringing everything to one side except h.
h=4·9·9·9
3·0.2·0.2
By dividing
h=1·9·9·3 ·100
1·0.1·0.1 ·100
h=3·9·9·100
1·1·1
h=24300cm
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