A is 10 years older than B and B is 15 yes younger than C. If the sum of their ages is equal to their fathers age., who is 40 years old., find the age of A, B and C
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A = 10 + B
B = C - 15
=> A = 10 + C - 15
Given sum is 40
=> A + B + C = 40
=>( 10 + C - 15)+ (C - 15) + C = 40
=>10 + C - 15 + C - 15 + C = 40
=> 3C -20 = 40
=> 3c = 40 + 20
3c = 60
c = 60/3
c = 20
Now A = 10 + C - 15
A = 10 + 20 - 15
A = 15
B = C - 15
B = 20 - 15
B = 5
Hope it helps dear friend ☺️✌️✌️✌️
B = C - 15
=> A = 10 + C - 15
Given sum is 40
=> A + B + C = 40
=>( 10 + C - 15)+ (C - 15) + C = 40
=>10 + C - 15 + C - 15 + C = 40
=> 3C -20 = 40
=> 3c = 40 + 20
3c = 60
c = 60/3
c = 20
Now A = 10 + C - 15
A = 10 + 20 - 15
A = 15
B = C - 15
B = 20 - 15
B = 5
Hope it helps dear friend ☺️✌️✌️✌️
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