Question

A is 100% more efficient than



b.B takes 50% more time than c to complete the work alone.If c take 6 days more than a

Answer 1

Answer:

since ‘A’ is 100% more efficient than ‘B’ ,

so A=B/2…..B=2A….(4)

since B takes 50% more time than C to complete the work alone,

so B=3C/2

C=4A/3…(1)

since C takes 6 days more than A to complete work alone,

C=6+A

From (1)

4A/3 =6+A

4A=18+3A

A=18….(2)

From (1)

C=4*18/3

C=24….(3)

From (4)

B=2A=2*18

B=36….(5)

A can complete the task in ‘A’ days

so 1 day, A can do (1/A)th of the work

similarly for B and C.

So in 1 day, together they can do {(1/A) +(1/B)+(1/C)} th of the total work

so together they can complete the Total Work in 1/{(1/A)+(1/B)+(1/C)} Days.

Together they can do the Total work in days

=1/(1/A)+(1/B)+(1/C)..(6)

solving the denominator first

=(1/18) +(1/36)+(1/24)

=(1/6) {(1/3)+(1/6)+(1/4)}

=(1/6)*{(4+2+3)/12}

=(1/6)*{9/12}

=(1/2)*(1/4)

=1/8

substituting the denominator in (6)

so, 1/(1/8) =8 days…..answer

together they can finish the work in 8 days…..Answer

Step-by-step explanation: