A is 2 times elder of b who is elder 3 timrs of
c. The average age of a b c is 27. Find the b age
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let the age of c is x
let the age of b is 3x
let the age of a is 2×3x=6x
average = 27
x+3x+6x/3=27
x+3x+6x=27×3
10x= 81
x=81/10
x=8.1
age of B=3x=3×8.1=24.3 years old
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let the age of b is 3x
let the age of a is 2×3x=6x
average = 27
x+3x+6x/3=27
x+3x+6x=27×3
10x= 81
x=81/10
x=8.1
age of B=3x=3×8.1=24.3 years old
please mark me brainlist
plzz plzz plzz plzz
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Here's your answer b=243/10
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