Question

A is 2 years older than B who is twice as old as C . If the total of their ages ( age of A,B,C) is 27, the how old is B​

Answer 1

Answer:

10

Step-by-step explanation:

Let the age of C be x.

Therefore, the age of B would be 2x.

And the age of A would be (2x + 2)

A.t.q.

x + 2x + (2x + 2) = 27

5x + 2 = 27

5x = 27–2

5x = 25

x = 25/5

x = 5

Therefore, age of B = 2x = 2*5 = 10

Answer 2

Answer:

10 years old

Step-by-step explanation:

Let the age of C be x.

This means B is 2(x) years old. B is 2x.

A is 2 years older than 2x. A is 2+2x.

A + B + C = 27

(2+2x) + (2x) + (x) = 27

2 + 5x = 27

2 + 5x - 2 = 27 - 2

5x = 25

(5x)/5 = 25/5

x = 5

C is 5 years old. But we need the age of B.

B is twice as old as C, 2x. 2(5) = 10

B is 10 years old.