Question

A is 20% faster than B and takes 20 mins for a certain distance.Time taken by B to cover double that distance is

Answer 1

Time taken by B is 48 minutes.

Step-by-step explanation:

Let the distance be 'x'

Let the speed of B be 'y'.

Let the speed of A be '$\dfrac{100+20}{100}y=\dfrac{120}{100}y=1.2y$'

Time taken by A = 20 min

So, We get that

$Distance=Speed\times time\\\\x=1.2y\times 20\\\\\dfrac{x}{y}=24$

If the distance is doubled for B = 2x

So, Time taken by B is given by

$\dfrac{Distance}{Speed}=\dfrac{2x}{y}=\dfrac{x}{y}\times 2=2\times 24=48\ minutes$

Hence, time taken by B is 48 minutes.

# learn more:

A took 45 minutes to walk 15 km. if b is 20% faster than a , how much time he will take to cover the same distance?

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