A is 20% less efficiency than B .if A can complete a work in 7 1/2 hours then in how much time together they can complete the same work ?
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Step-by-step explanation:
20% = 1/5
efficiency ratio of A& B
= (5-1) : 5 = 4 : 5
let A's 1 hour's work = 4 units
total work = 4 × 7 1/2 = 30 units
(A + B)'s 1 hour's work = 4 + 5 = 9 units
so together they can complete the work in = 30/9 = 3 1/3 hours
= 3hrs 20 mins Answer
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