Math, asked by plutonium1774, 8 months ago

A is 20 years older than B. 5 years ago, a was 3 times as old as B. Find their present ages

Answers

Answered by MsPRENCY
5

Answer :

Present age of A : 35 years

Present age of B : 15 Years

\rule{100}2

Let present age of B be ' x ' years. So, present age of A will be ' 20 + x '

5 years ago

  • A = 20 + x - 5
  • B = x - 5

According to question :

20 + x - 5 = 3 ( x - 5 )

⇒ 15 + x  = 3x - 15

⇒ 15 + 15 = 3x - x

⇒ 30 = 2x

⇒ 30/2 = x

∴ x = 15

  • Present age of B is 15 years
  • Present age of A : 20 + 15 = 35 years

\rule{200}2

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