Question

A is 20 years older than
b. He is also 6 times older than
b. Find their ages

Answer 1

Answer:

A = 24

B = 4

Step-by-step explanation:

20 + B = A (equation 1)

B = A - 20 (rearrange equation 1)

B * 6 = A (equation 2)

Insert value of B into equation 2:

(A - 20) * 6 = A

6A - 120 = A

6A - A = 120

5A = 120

A = 24 years old

Substitute A into equation 1:

20 + B = 24

B = 24 - 20

B = 4 years old

Answer 2

$\huge\mathfrak{\bf{\underline{\underline{\mathsf{Question\ :}}}}}$

$\longrightarrow\mathsf{A \: is \: 20 \: Years \: older \: than \: B . \: He \: is \: also \: six }$

$ㅤㅤ\mathsf{times \: as \: old \: as \: B. \:Find \: their \: present \: ages. }$

$\huge\mathfrak{\bf{\underline{\underline{\mathsf{Solution\ :}}}}}$

$☞︎︎︎ \: \mathsf{Let \: age \: of \: B \: be \: x \: years.}$

$☞︎︎︎ \: \mathsf{A \: is \: 20 \: years \: older \: than \: B}$

$\therefore \: \mathsf{A \: is \: x + 20 \: year \: old.}$

$☞︎︎︎ \: \mathsf{A \: is \: also \: six \: times \: as \: old \: as \: B}$

$\therefore \: \mathsf{x + 20 = 6x}$

$➪ \: \: \mathsf{5x = 20}$

$➪ \: \: \mathsf{x = \frac{ \cancel{20} \: ^{4} }{ \cancel5 ^{1} } }$

$➪ \: \: \mathsf{ \boxed{ \blue{\mathsf{Answer :\ x = 4}}}}$