Question

A is 24 years elder than B .10 years back ,age of A was 5 times the age of B . Find their present ages.

Answer 1

${ \red{ \huge{ \underline{ \underline{ \mathfrak{Question:-}}}}}}$

▪A is 24 years elder than B. 10 years back, age of A was 5 Times the age of B. Find their present ages..

${ \red{ \huge{ \underline{ \underline{ \mathfrak{S olution:-}}}}}}$

▪ Let the age of B be x years...

${ \pink{ \bold{according \: to \: the \: question-}}}$

☆ A is 24 years elder than B

therefore,,

${ \bold{age \: of \: A = (x + 24)years}}$

● it's given in the question that

${ \pink{ \bold{10 \: years \: before}}}$

▪ age of A was 5 Times the age of B...

age of A 10 years before = ( (x+24) - 10)) years

age of B 10 years before = (x-10) years

${ \boxed{ \bold{ \red{ \: \: age \: of \: A = 5(age \: of \: B) \: \: }}}}$

▪ it can be represented in the form of equation as follows ...

${ \bold{((x + 24) - 10) = 5(x - 10)}}$

${ \bold{ \implies{x + 14 = 5x - 50}}}$

${ \bold{ \implies{5x - x = 50 + 14}}}$

${ \bold{ \implies{4x = 64}}}$

${ \boxed{ \bold{ \red{ \: \: x = 16 \: \: }}}}$

thus,

▪present age of B = x years = 16 years

therefore,

▪ present age of A = (x+24)years = ( 16+24)years = 40 years

${ \bold{ \red{ present \: age \: of \: A \: = 40years}}}$

${ \red{ \bold{ present \: age \: of \: B \: = 16years}}}$

Answer 2

Qᴜᴇsᴛɪᴏɴ:-

A is 24 years elder than B. 10 years back, age of A was 5 times the age of B. Find their present ages.

Aɴsᴡᴇʀ:-

Present ages:-

Let the present age of B be x years

Then, the present age of A will be (x + 24) years

10 years back:-

Age of B = (x - 10) years

Age of A = (x + 24 -10) years = (x + 14) years

Given: 10 years back age of A was 5 times age of B

A/q

(x + 14) = 5(x - 10)

➮x + 14 = 5x - 50

➮14 + 50 = 5x - x

➮64 = 4x

➮x = 64/4

➮x = 16 years

Present ages:-

Present age of A = (x + 24) years = (16 + 24) years = 40 years

Present age of B = x years = 16 years