Question

a is 24 years older than B 10 years back age of a was 5 times the age of B find their present ages​

Answer 1

$\mathfrak{Answer}$

16 years, 40 years

$\mathfrak{explanation}$

Let the age of B be x

Age of A = 24+x

Age of B ten years ago = x-10

Age of A ten years ago = 24+x-10

According to Question:

24+x-10 = 5(x-10)

24+x-10 = 5x-50

24-10+x = 5x-50

14+x = 5x-50

14+50 = 5x-x

64 = 4x

x = $\frac{64}{4}$

x = 16

Present age of B = 16 years

Present age of A = 16+24= 40 years