Math, asked by saripallimeenapbccfu, 1 year ago

A is 24yrs elder than B. 10years back age of A was 5 times the age of B.Find the present ages

Answers

Answered by ashimadangi
1
let present age of B=x years
then ,present age of A will be = ( x+24 ) years
10 years back age of B would be = ( x- 10 ) yrs
10 years back age of A = (x+24-10)years
ATQ
5 (x-10) = x+14
5x-50 = x+14
4x =64
x=64÷4
x=16
hence, present age of B = 16years
present age of A =16 + 24 =40 years

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