Math, asked by pratyushsinha48, 1 year ago

A is 25 years older than B.
In 15 years a will be twice
of B find the present age
of A . and B in detail​

Answers

Answered by pradnya250604
0

Answer:

A=B+25         (1)

AFTER 15 YEARS

A+15=2(B+15)

B+25+15=2B+30           (USING 1)

B+40=2B+30

10=B

IN EQ 1, A=25+B=25+10=35

Step-by-step explanation:

Answered by popelbd
0

Answer:

A = 35 Years

B = 10 Years

Step-by-step explanation:

Present Age of A =35 & B = 10

A-B=35-10= 25

After fifteen years:

A=35+15 =50

B=10+15=25 ; So Age of A (50) is double than B (25).

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