Question

A is 29 years older than B, B is 3 years older than C and D is 2 years younger than C. Two years hence, A's age will be twice the combine ages of B, C and D. Find the present age of A​

Answer 1

Answer: Let D’s age be = X years

Then C’s age = (X + 2) years,

B’s age = (X + 5) years

A’s age = (X + 34) years.

Two years hence A’s, B’s, C’s and D’s ages will be X + 36, X + 7, X + 4 and X + 2 years respectively.

So, we have: 2 (X + 2 + X + 4 + X + 7) = X + 36

OR X = 2 So,

A’s age = 36 years;

B’s age = 7 years,

C’s age = 4 years;

D’s age = 2 years