A is 3 times older than B. four years back , age of C was twice the age of A. In 4 years A will be 31 years ,then what is the age of B n C?
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let the age of B be x
thus the age of A will be x+3.
four years back the age of A was x-1
and the age of C was 2x-2
after 4 years the age of A will be x+7=31
x=24 - age of B
x+3=27 age of A
age of C =2x-2+4=2x+2=48+2=50.
thus the age of A will be x+3.
four years back the age of A was x-1
and the age of C was 2x-2
after 4 years the age of A will be x+7=31
x=24 - age of B
x+3=27 age of A
age of C =2x-2+4=2x+2=48+2=50.
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