Question

A is 3 years older than B. Eight years ago, 6/5 times A’s age exceeded three-fifth of B’s age by 6 years. What is the current age of B?

Answer 1

Answer:

12 years

Step-by-step explanation:

Let A's age be (x + 3) yrs

Let B's age be (x) yrs

8 years ago,

A's age = (x+3) - 8 =  x -5

B's age = x - 8

6/5(x-5)  = 3/5 (x-8) + 6

6x/5 - 6 = 3x/5 -24/5 + 6

6x/5 - 3x/5 = -24/5 + 12

6x/5 - 3x/5 = -24/5 + 12

6x-3x/5 = 36/5

3x/5 = 36/5

3x = 36 (36/5 x 5/1)

x = 12

Check:

A's age (8 years ago) = 12 - 5 = 7

B = 12 - 8 = 4

6/5 x 7 = 8.4 years

3/5 x 4 = 2.4 years

8.4 - 2.4 = 6