) A is 4 1 A car of mass 2000 kg moving in a road with velocity of goknad hors The break is applied so that it come to rest after 5 seconds - Calculate the readavation produce. and distance covered by car before coming to rest. How much force should be applied through break to stop the car.
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Answer:
Given,
Mass of car, M=2000kg
Velocity, V=72×
18
5
=20ms
−1
Apply kinematic equation of motion
v
2
−u
2
=2as
0−20
2
=2a×20
a=−10ms
−2
Breaking force, F=ma=2000×10=20 kN
Apply first kinematic equation
v=u+at
t=
a
v−u
=
−10
0−20
=2 sec
Breaking force is 20 kNand time is 2sec
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