Question

A is 4 times as old as B. 10 years ago , A was 10 times as old as B. find the present age of B.​

Answer 1

Step-by-step explanation:

Let B be x years old.

.

Now:

B = x

A = 4x

.

Ten years ago,:

B = x - 10

A = 4x - 10

.

Ten years ago, A was 10 times as old as B:

4x - 10 = 10 (x - 10)

.

Solve x:

4x - 10 = 10 (x - 10)

4x - 10 = 10x - 100

10x - 4x = 100 - 10

6x = 90

x = 15

.

Find their present age:

B = x = 15

A = 4x = 4(15) = 60

.

Answer: B is 15 years old

Answer 2

Answer:

ans= the present age of B is 15 years

Step-by-step explanation:

Let B be x year old

according to question

A is 4 times as old as B

therefore A= 4x

Now

B = x

A = 4x

ten years ago

B = x-10

A= 4x-10

ten years ago A was 10 times as old as B

the equation will form

4x-10 = 10(x-10)

4x-10 = 10 x- 100

100-10 = 10x- 4x

90 = 6x

90/6 = x

15 = x

since x is the age of be so,

the age of B = 15 years old