Question

'A' is 40% less efficient than 'B' who can do the same work in 20% less time than 'C'.IfA and B together
can complete 80% of work in 12 days, then in how many days 60% of work can be completed by B and C
together.
1. 2 days
2.4days
4.8 days
5.10 days​

Answer 1

Answer:

Let C's efficiency be 100, B's will be 80 and A's 112. Reducing we get the ratios as 28:20:25

No.of days required for work ( inversely proportional) LCM =700

Days: A:B:C = 25 : 35: 28

When difference of days between A and C is 3 , C takes 28 days. Hence when actual difference is 6 days C will take 6*28/3 = 56 days. Therefore A will take 50 days.

B is 40% less efficient than A and hence takes 50*35/25 = 70 days..