Question

'A' is 40% less efficient than 'B' who can do the same work in 20% less time than 'C'.IfA and B together can complete 80% of work in 12 days, then in how many days 60% of work can be completed by B and C together.​

Answer 1

Answer:

70 Days

Step-by-step explanation:

Let C's efficiency be 100, B's will be 80 And A's 112 . reducing we get the ratios as 28:20:25

Number of days required for work ( inversely proportion ) LCM= 700

Days A:B:C = 25:35:28

When difference of days between A and C is 3 ,

C takes 28 days. Hence when atcual difference is 6 days C will take 6*28/3 = 56 days. Therefore A will take 50 days.

B is 40% less than efficient than A and hence take 50*35/25 = 70 days.