Math, asked by bhartichodha, 1 year ago

a is 5 times as old as B after 10 years a will be three times as old as B will be then find the present ages of a and b​

Answers

Answered by Mrpolite
1

Answer:

Let the age of B be x.

Then age of A = 5x

B's age after 10 years = x+10

A's age after 10 years = 5x+10

also A's age after 10 years = 3(x+10)

Therefore,

5x+10 = 3(x+10)

5x+10 = 3x+30

2x = 20

x = 10

5x = 50

Hence, present age of A is 50 years and B is 10 years

Hope it helps you

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