A is 50% as efficient as B. C does half of the work done by A and B together in same time in same time. If C alone does the work in 20 days, then A, B and C together can do work in: (a) 2 5 days 3 (b) 2 6 days 3 (c) 6 days (d) 7 days (e) None of these
Answers
Answered by
0
Step-by-step explanation:
C does half work of A & B
Work done by C in a day is 1/40
C = 1/(A+B) 2
1/40 = 1/(A+B) 2
2/40 = 1/A+B
1/A+B = 1/20
So A & B together take 20 days to complete a work
Now A, B & C together take
1/A + 1/B +1/C
= 1/20 + 1/40
= 3/40
= 40/3 days
= 13.33 days
Similar questions