A is 6 years older than B, who is 4 times as old as
C. If the sum of their ages is 33, what is A's age?
Answers
Answered by
1
Answer:
18
Step-by-step explanation:
A = B+6
B= 4C
C= B/4
A + B + C = B + B + 6 + B/4= 9B/4 + 6
9B/4 + 6 = 33
9B/4= 27
B = 27*4/9
B= 12
so A = B+6
age of A = 12+6=18
Answered by
0
Answer:
10.5 year
Step-by-step explanation:
a=6+x
b=x
c=4x
6+x+x+4x=33 (given)
6+6x=33
6x=33- 6
6x= 27
x= 27÷6
x=10.5
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