Math, asked by k6mannan, 11 months ago

A is 6 years older than B, who is 4 times as old as
C. If the sum of their ages is 33, what is A's age?​

Answers

Answered by pranavgreat
1

Answer:

18

Step-by-step explanation:

A = B+6

B= 4C

C= B/4

A + B + C = B + B + 6 + B/4= 9B/4 + 6

9B/4 + 6 = 33

9B/4= 27

B = 27*4/9

B= 12

so A = B+6

age of A = 12+6=18

Answered by swara810
0

Answer:

10.5 year

Step-by-step explanation:

a=6+x

b=x

c=4x

6+x+x+4x=33 (given)

6+6x=33

6x=33- 6

6x= 27

x= 27÷6

x=10.5

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