Question

A is 9 years older than


b. after 10 years a will be twice as old as b was 10 years ago . find present ages

Answer 1

solving ,here is the answer in photo

Answer 2

let age of A be x
and age of B be y.

X= y+9
x-y = 9 ...(1)

Age of A after ten years = x+10
Age of B beforev10 years = y-10

A.T.Q.
x+10 = 2(y-10)
x+10 = 2y-20
x-2y= -30.... (2)

solving (1) & (2)
x-y = 9
x-2y= -30
- + +
_________
y = 39 yrs.

x = y+9 = 39+9 = 48 yrs.


age of A = 48 yrs.

age of B = 39 years


i hope this will help you