Question

A is a digit and 3 A18 is a multiple of 6. Find the value of A​

Answer 1

Answer:

0

Step-by-step explanation:

The divisibility property of 6 -

When the number is divisible by 2 and 3.

It is divisible by 2

3+1+8=12

Thus A should be 0.

Hope it helps...

Answer 2

Step-by-step explanation:

Given :-

A is a digit and 3 A18 is a multiple of 6.

To find:-

Find the value of A?

Solution:-

Given number = 3 A18

Given that it is a multiple of 6

=> It is divisible by 6

=> It is divisible by both 2 and 3

Checking for divisibility by 2:-

The number 3A18 is divisible by 2 because it has 8 is in its ones place.

Checking for divisibility by 3:-

The sum of the digits in the given number must be divisible by 3

=> 3+A+1+8

=> 12+A

So 12 is a multiple of 3

Then

The possible values of A are 0,3,6,9,...

Therefore, A = 0

Answer:-

The least possible value of A is 0

Check:-

If A = 0 then the number = 3018

3018/6 = 503

It is a multiple of 6 .

Verified the given relation.

Used formulae:-

Divisibility by 2:-

A number is divisible by 2 , If a number has one of the digits 0 or 2 or 4 or 6 or 8 in its ones place .

Divisible by 3:-

A number is divisible by 3, if the sum of all the digits is divisible by 3.

Divisibility by 6:-

A number is divisible by 6,if the number is divisible by both 2 and 3.