Question

A is a digit and 3A15 is a multiple of 9. Which of the following can be the value of A?

Answer 1

Answer:

rule of the divisibility of 9 is sum of all the digit in a number is divisible the complete number is divisible,so 3+A+1+5 ,if we put A=9 then the number is multiple of 9

Answer 2

The answer is Zero. If A = 0, 3A15 becomes a multiple of 9

Given:

The number 3A15 is a multiple of 9

Find:

Find the value of A, such that the number becomes divisible by 9

Solution:

• The rule of divisibility of 9 is that the sum of digits of the number should be divisible by 9.
• Then the number becomes divisible by 9.
• Here the sum of digits is = 3+1+A+5 = 9+A
• If A =0, then the sum becomes 9.
• Which is divisible by 9.
• Thus the whole number becomes divisible by 9.
• Thus the value of A is zero
• #SPJ3