Question

A is a digit and 3A15 is a multiple of 9 which of the following can be the value of A.​

Answer 1

Explanation:

The divisibility test of 9 says that if the sum of the digits of a number is divisible by 9, it is a multiple of 9.

In this case,

$3 + a + 1 + 5 = 9 + a$

must be equal to 9.

This means that the only two numbers possible in this situation for A are 0 and 9.

Answer: 0, 9

I hope this helps. :D

Answer 2

Answer:

Therefore, the value of $A$ is $0$ or $9$.

Step-by-step explanation:

Given:

$A$ is a digit and $3A15$ is a multiple of $9$

To Find:

To calculate the Value of $A$

Step 1

If $3A15$ exists a multiple of $9$ then it must follow the divisibility rule of $9$.

Now, the divisibility rule of $9$ is :

Any number whose totality of all digits exists $9$ or multiple of $9$ , then it is divisible by $9$.

Step 2

Since  $3A15$ exists a multiple of 9 so sum of its digits will be $9$ or multiple of $9$

The totality of digits of $3A15 = 3+A+1+5$

The totality of digits of $3A15 = 9+A$

Since $A$ is also a digit so it has to be zero or nine to become nine or multiple of $9$.

So, the value of $A$ is $0$ or $9$.

#SPJ2