Question

a is a divalent in acidicradical and b is trivalentbasic radical then formula of compound formed by a and b is​

Answer 1

Answer:  a. 32 g of oxygen

Number of moles in O2=Mass of O2 in gramsMolecular mass of O2

                                                   =3232=1mol                    

1 mole of O2 contains-----6.022 x 1023 molecules

b. 90 g of water

Number of moles in water=Mass of water in gramsMolecular mass of water

                                                      =9018=5moles

5 moles of H2O contains-----5 x 6.022 x 1023 molecules = 30.11 x  1023 molecules

c. 8.8 g of CO2

   Number of moles in CO2=Mass of CO2 in gramsMolecular mass of CO2                                           = 8.844= 0.2mol

0.2 moles of CO2 contains-----0.2 x 6.022 x 1023 molecules = 1.2044 x  1023 molecules

d. 7.1 g of chlorine

 No. of moles in chlorine=Mass of chlorine in gramsMolecular mass of chlorine                                         =7.171= 0.1mol

  0.1 moles of Cl2 contains-----0.1 x 6.022 x 1023 molecules = 0.6022 x  1023 molecules

Explanation: