Question

A is a point at a distance of 10m from the centre O of a circle of radius 6cm. AP and AQ are the tangent to the circle at P and Q. If tangent BC is drawn at a point are lying on the minor arc PQ to intersect AP at B and AQ at C, find the perimeter of triangle ABC

Answer 1

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BP = BR and CR = CQ

Perimeter of ΔABC = AB + BR + RC + CA

= AB + BP + QC + CA

= AP + QA (AP = QA)

= 2AP

ΔAPO

AO²=AP²+PO²

13² = AP² + 5²

AP² = 144

AP = 12

The perimeter of the ΔABC

2 x 12 = 24 cm is the answer

Answer 2

Answer:

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Step-by-step explanation:

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