Question

A is a point on the x-axis and B is (-7,9). Distance between the points A and B is 15 units.Find the coordinates of point A.​

Answer 1

Answer:

hope it helps u solve it

Answer 2

Define coordinate A:

Let x be the x-coordinate of A

A is a point on the x-axis

⇒ The y-coordinate of A is 0

Therefore A = (x, 0)

Find the distance between A and B:

A = (x, 0) , B  = (-7, 9)

$\text{Distance = }\sqrt{(Y_2 - Y_1)^2 + (X_2 - X_1)^2}$

$\text{Distance = }\sqrt{(0-9)^2 + (x+7)^2}$

$\text{Distance = }\sqrt{81 + (x + 7)^2}$

Solve x:

$\text{Distance } = 15 \text{ units}$

$\sqrt{81 + (x + 7)^2} = 15$

${81 + (x + 7)^2 = 15^2$

$81 + x^2 + 49 + 14x = 225$

$x^2 + 14x - 95 = 0$

$(x + 19)(x - 5) = 0$

$x = - 19 \text{ or } x = 5$

Answer: The coordinate of A is either (-19, 0) or (5, 0)