A is a point on the X-axis and B is a point on the Y-axis such that 2.OA=3.OB The equation of a locus of the point P which divides seg AB externally in the ratio 4:3 is
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A and B are any two points on the positive x and y−axis respectively satisfying 2(OA)+3(OB)=10. If P is the middle point of AB then the locus of P is:
A
2x+3y=5
B
2x+3y=10
C
3x+2y=5
D
3x+2y=10
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Correct option is A)
According to question,
P is the mid point of AB.
So, let P(x,y).
Therefore, from mid-point formulai.e.,mid point (x,y) of (x1,y1),(x2,y2) is
x−2x1+x2,y=2y1+y2
Hence
A(2x,0) & B(0,2y)
And, OA=2x & OB=2y
So, locus of P =>2(2x)+3(2y)=10
=> 2x+3y=5
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