Question

A is any point with in a triangle PQR whose side are 5 cm 7 cm 10cm respectively. prove that, AP+ AQ +AR is greater than 11 cm.​

Answer 1

Answer:

AP+AR+AQ > 11 cm

Step-by-step explanation:

Sum of two sides is greater than three sides.

==> AP+AQ > 5cm

==> AP+AR > 7cm

==> AQ + AR > 10cm

Add all equations.

2 AP + 2 AR + 2 AQ > 5 + 7 + 10

2 AP + 2 AR + 2 AQ > 22

2(AP+AR+AQ) > 22

AP + AR + AQ > 11 cm

#BeBrainly

Answer 2

Answer:

AP+AR+AQ > 11 cm

Step-by-step explanation:

sum of two sides is greater than 3 sides

AP+AQ > 5cm

AP + AR > 7cm

AQ + AR > 10cm

Now, add all equations

2AP+2AR+2AQ>5+7+10

OR, 2AP+2AR+2AQ > 22

OR, 2 (AP+AR+AQ) > 2*11

Therefore, AP+AR+AQ > 11cm