Question

A is any point within a
triangle PQR whose sides are 5cm, 7cm, 10cm respectively. prove that, AP + AQ + AR > 11cm. ​

Answer 1

let a be any point inside triangle which is at minimum distance of 1 cm from any point.

in triangle APR

as we know sum of two side of triangle is greater than third side. so, AP + AR = more than 10 cm and A is at minimum distance of 1 cm from q

hence proved AP+AQ+AR> 11 cm