Question

A is as much younger to b as he is older to
c. If the sum of the ages of b and c is 48 years, what is the present age of a?

Answer 1

Answer:

A is younger than B

and A is older than C

A/q

(age of A) - (age of C) = (age of B) - (age of A)

⇒2A = B +C

and B+C = 48______(given)

so, 2A = 48

age of A = 24 years

OR

Step-by-step explanation:

Given A is younger than B as he is elder than C. 

Let the difference between the age of A and B and A and C which is equal be 'y'.

Now,A=B-y

and A=C+y

Now A=B-y

therefore,y=B-A,which is the L.H.S

Now A=C+y

Therefore ,y=A-C,which is the R.H.S

Now,L.H.S-R.H.S

ie;y-y=(B-A)-(A-C)

        0=B-A-A+C

        0=B+C-A-A 

         0=48-2A

       ie;48=2A

Therefore A=48/2

                   =24.