Question

A is at (4,-6) B is at (-1,-3) p is a point on x axis which is equidistant from a to b what ware the coordinates of P​

Answer 1

Answer:

$x = \frac{x1 + x2}{2} \: \: y = \frac{y1 + y2}{2}$

this is mid point formula

Step-by-step explanation:

• P is equidistant from A and B that means P is a mid point.
• Also we are given that P lies on x-axis so, y=0.
• Taking
• $a = (4. - 6) \: where \: 4 = x1 \: \: \: and \: - 6 = y1$
• similarly
• $b = ( - 1. - 3) \: where \: - 1 = x2 \: \: and \: - 3 = y2$
• now put the value to find the value of x.
• $p = \frac{4 + ( - 1)}{2} \\ = \frac{3}{2} \\ so \: p = ( \frac{3}{2} .0)$

Hope u have understood the solution

Answer 2

Answer:

The Coordinate of P=(-7, 0)

your answer