Question

a is equal to root3-root2 /root3+ root2, equals to root3+root2/root3-root2 find a square +b square​

Answer 1

$\huge\tt\underline\orange{Answer}$

a= √3-√2/√3+√2

b = √3+√2/√3-√2

Here

a= √3-√2/√3+√2= (√3-√2)(√3-√2)/(√3+√2)(√3-√2) [Multiplying both numerator and denominator by √3-√2]

=> a = 3+2-2√6/3-2= 5-2√6

Similarly b= √3+√2/√3-√2

multiplying both numerator and denominator by √3+√2

= (√3+√2)(√3+√2)/ (√3-√2)(√3+√2)

= 3+2+2√6/ 3-2

= 5+2√6

so

a^2+b ^2= (5-2√6)^2+ (5+2√6)^2. (applying the identity (a+b)^2+(a-b) ^2= 2(a^2+b^2) ]

we have

2{(5)^2+ (2√6)^2}

= 2{25+24}

= 2{49}

= 98

hope it helps ✌

Answer 2

Answer:

a= root3-root 2/ root3+root 2 after rationalizing , a= 5-(2root6)

b= root3+root 2/ root3-root 2 after rationalizing , a= 5+(2root6)

(a²+b²)=(a+b)²-2

[5-(2root6) + 5+(2root6)]²-2   (2root6 and -2root6 is cancelled )

10^2-2

100-2

98 ANSWER

PLS MARK BRAINLIEST