Question

A is four time as old as B. 10 years ago A was 10 times as old as B .find the percentage of B ​

Answer 1

Step-by-step explanation:

Let B's age be x years. Then A's age is 2x years.

Ten years ago, their ages were, respectively, x-10 and 2x -10 years. Thus, we have

2x−10=4(x−10)

2x−10=4x−40

2x=30

∴x=15

So, B is 15 years old and A is 30 years old.

Answer 2

Step-by-step explanation:

A : B

4 : 1

{10x +10}/x +10 = 4/1

4x +40 = 10x +10

6x =30

x =5

x+10 = 5+10=15