Question

a is four times as old as B 10 years ago a was 3 times as old as B find the present age of B

Answer 1

let the age of B = x
age of A = 4x

Ten years ago

Age of B = x - 10
Age of A = 3(x - 10)

According to question

x - 10 = 3 (x - 10)
x - 10 = 3x - 30
3x - x = 30 - 10
2x = 20
x = 20/2 = 10

Age of B = 10 years

Age of A = 4x = 4 × 10 = 40 years