A is four times efficient than B and A can complete a work in 90 days less time than B. Find in how many days both can complete the work.
(a) 30 days
(b) 20 days
(c) 40 days
(d) 50 days
Step by step explanation please.
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Answer:
Let A can do the work in x days.
Therefore B can do the work in 3x days.
A's one day work = 1/x
B's kne day work = 1/3x
Thus, if both A and B work together, part of work done by them in one day = 1/x +1/3x
=> Work done by them in 30 days = 30(1/x + 1/3x)
=> 30(4/3x) = 1
=> 40/x = 1
=> x = 40.
Thus, A takes 40 days to complete the work and B takes (40×3=120) days to complete the work respectively.
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