Question

A is know to hit the target in 2 out 5 shot. B is known to hit the target in 3 out of 4 shots . Find the probability of the target being hit when both try?

Answer 1

Step-by-step explanation:

p = 2/5*3/4 + 2/5*1/4 + 3/5*3/4 = (6+2+9)/20 = 17/20

Answer 2

Given,

P(A) = 2/5

P(B) =3/4

To find,

We have to find the probability of the target being hit when both try.

Solution,

The probability of the target being hit when both tries is 17/20.

P(A) = 2/5

P(A not) = 1-P(A)

P(A not) = 1-2/5

P(A not) = 3/5

P(B) = 3/4

P(B not) = 1-P(B)

P(B not) = 1-3/4

P(B not)= 1/4

P( of target being hit) = P(AB) +P(AB not) + P( A not B)

                                   = 2/5*3/4 + 2/5*1/5 + 3/5 * 3/4

                                   = 17/20

Hence, the probability of the target being hit when both tries is 17/20.