A is moving towards bombay from delhi and b is moving towards delhi from bombay . Speed of a is 50 km/hr and b 60 km/hr. When a and b meets b travel 120 km more than a . Find the time after they meet.
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let distance of A is xkm then B is x+120km
s=d/t => s1/d1=s2/d2 => 50/x = 60/(x+120)
5x+600=6x =>x=600km
time taken t=d/s => t=600/50=12hours.
s=d/t => s1/d1=s2/d2 => 50/x = 60/(x+120)
5x+600=6x =>x=600km
time taken t=d/s => t=600/50=12hours.
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