A is now half as old as his father. 12 years ago the father was three times as old as his A. Find their ages
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Answered by
15
hello Akamit
#ur Ans
___________
Let the age of A be x
then his father age will be 2x
Now, 12 years ago
==>3 (X-12) = 2x-12
==> 3x -48 = 2x -12
==> 3x -2x = -12 +48
==> X = 36
So the age of A is 36 years
&
his father age be 2x = 72 years
:-)✌☺
#mark as brainlist
#ur Ans
___________
Let the age of A be x
then his father age will be 2x
Now, 12 years ago
==>3 (X-12) = 2x-12
==> 3x -48 = 2x -12
==> 3x -2x = -12 +48
==> X = 36
So the age of A is 36 years
&
his father age be 2x = 72 years
:-)✌☺
#mark as brainlist
Answered by
1
Let s be the son’s age and f be the father’s age, then
f2=sf2=s or 2s=f2s=f
s+f=72s+f=72
s=72−fs=72−f
f2=72−ff2=72−f
f=144−2ff=144−2f
3f=1443f=144
Therefore, we can trivially calculate that the father is 48. Since the son is half that age, he must be 24.
f2=sf2=s or 2s=f2s=f
s+f=72s+f=72
s=72−fs=72−f
f2=72−ff2=72−f
f=144−2ff=144−2f
3f=1443f=144
Therefore, we can trivially calculate that the father is 48. Since the son is half that age, he must be 24.
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