Question

A is now half as old as his father. 12 years ago the father was three times as old as his A. Find their ages

Answer 1

hello Akamit

#ur Ans
___________

Let the age of A be x
then his father age will be 2x

Now, 12 years ago

==>3 (X-12) = 2x-12

==> 3x -48 = 2x -12

==> 3x -2x = -12 +48

==> X = 36

So the age of A is 36 years
&
his father age be 2x = 72 years

:-)✌☺

#mark as brainlist

Answer 2

Let s be the son’s age and f be the father’s age, then

f2=sf2=s or 2s=f2s=f

s+f=72s+f=72

s=72−fs=72−f

f2=72−ff2=72−f

f=144−2ff=144−2f

3f=1443f=144

Therefore, we can trivially calculate that the father is 48. Since the son is half that age, he must be 24.