A is one third as old as B and B is half as old as C. if the total ages
are 180 years find their ages separately.
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Answer:
Answer is 60
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hi
let the age of c be x
then b= 1/2x
a=1/2×1/2×x=1/4x
sum = 180 = x+1/2x+1/4x
180=4x+2x+x=7x/4
x=180×4/7=102
c= 102
b= 51
a =30
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