A is the point (0,8) and B is the point (8,6). Find the point C on the y-axis such that angle ABC is 90 degrees. Please show you work.
Answers
C = (0,8)
Step-by-step explanation:
If
A = (0,8) = (x1, y1) say
Then A lies on y axis
B=(8, 6) = (x2, y2) say
If C lies on y axis then C is of the form (0, a)
Since AB and BC are perpendicular ( since angle ABC =90°)
(Slope of AB) (Slope of BC) =-1
(6-8)/(8-0)=(a-6)/(0-8)
2=a-6
a=8
The required coordinate C (0, -26)
Given:
A is the point (0,8) and B is the point (8,6)
To find:
Find the point C on the y-axis such that angle ABC is 90 degrees
Solution:
Given A (0,8) and B (8,6)
Let (x, y) be point C
Given that C lies on y -axis, then the coordinate of x = 0
Then the required point C(x,y) = (0, y)
Given that the angle ABC = 90°
If we join AB and BC then line AB will be perpendicular to line BC
As we know
The Product of slopes Perpendicular lines AB and BC = -1
A (0,8) and B (8,6)
Slope of AB = (6 - 8) / (8 -0) = -2/8 = -1/4
B (8, 6) and C (0, y)
Slope of BC = (y - 6)/(0-8) = (y - 6)/-8
⇒ Slope of AB × Slope of BC = - 1
⇒ Slope of AB = - ( 1/Slope of BC )
⇒ -1/4 = - [-8 /(y-6) ]
⇒ 1(y-6) = (-8)(4)
⇒ y-6 = -32
⇒ y = - 26
The required coordinate C (0, -26)
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