Question

'a' is the smallest odd prime number. if n is smallest 2 digit number by which a(a^2 - 1) is divisible, then find the sum of digits of n

Answer 1

a is smallest odd prime number=3

3(9-1)=3×8=24

smallest two digit number that divide 24 is 12....

so sum of digits of 12 is (1+2=3)

so ans is 3

Answer 2

Answer:

3

Step-by-step explanation:

Smallest odd no. is 3

so,

a(a^2 -1)

=> 3 ( 3 ^ 2 -1)

=> 3 (9 - 1)

=> 3 * 8

=> 24

Smallest 2 digit no. factor of 24 is 12

so,

Sum of it's digits is

1 +2 = 3

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