A is three times as old as
b.C was twice as old as a four years ago.In four years time , a will be 31. What are the present ages of b and c
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therefore a=27
b=9
c=50
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Answer:
Step-by-step explanation:
let the age of 'a' 'b' and 'c' be 'x' , 'y' and 'z'
a.c.p
x = 3y
z-4 = 2(x - 4)
x + 4 = 31
x = 27
z - 4 = 2(27 - 4)
z - 4 = 46
z = 50
x = 3y
27 = 3y
y = 9
therefore age of 'b' = 9
age of 'c' = 50
and age of 'a' = 27
verification
z - 4 = 2(x - 4)
50 - 4 = 2(27 - 4)
46 = 46
hence verified
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